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Terminal: explicitly assume that fopen(stdin) will not fail

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Dylan K. Taylor 2020-04-15 11:12:03 +01:00
parent 5c9419b55c
commit 2622c34542
1 changed files with 1 additions and 0 deletions
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src/pocketmine/utils/Terminal.php
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@ -90,6 +90,7 @@ abstract class Terminal{
private static function detectFormattingCodesSupport() : bool{ private static function detectFormattingCodesSupport() : bool{
$stdout = fopen("php://stdout", "w"); $stdout = fopen("php://stdout", "w");
if($stdout === false) throw new AssumptionFailedError("Opening php://stdout should never fail");
$result = ( $result = (
stream_isatty($stdout) and //STDOUT isn't being piped stream_isatty($stdout) and //STDOUT isn't being piped
( (